6y^2+7y-9=0

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Solution for 6y^2+7y-9=0 equation: 



6y^2+7y-9=0

a = 6; b = 7; c = -9;
Δ = b2-4ac
Δ = 72-4·6·(-9)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{265}}{2*6}=\frac{-7-\sqrt{265}}{12}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{265}}{2*6}=\frac{-7+\sqrt{265}}{12}
$

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